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{
    "url": "https://mailman.amsat.org/hyperkitty/api/list/[email protected]/email/BZICX65I4JV252QXLAX2QFGJF5UXPISD/",
    "mailinglist": "https://mailman.amsat.org/hyperkitty/api/list/[email protected]/",
    "message_id": "[email protected]",
    "message_id_hash": "BZICX65I4JV252QXLAX2QFGJF5UXPISD",
    "thread": "https://mailman.amsat.org/hyperkitty/api/list/[email protected]/thread/BZICX65I4JV252QXLAX2QFGJF5UXPISD/",
    "sender": {
        "address": "grant (a) ghengineering.co.uk",
        "mailman_id": "74a4d29508634e669020884f51007f55",
        "emails": "https://mailman.amsat.org/hyperkitty/api/sender/74a4d29508634e669020884f51007f55/emails/"
    },
    "sender_name": "Grant Hodgson",
    "subject": "[amsat-bb] Re: receiver sensitivity conversion question",
    "date": "2007-03-22T09:33:12Z",
    "parent": null,
    "children": [],
    "votes": {
        "likes": 0,
        "dislikes": 0,
        "status": "neutral"
    },
    "content": "Tyler\n\nUsually, an RF voltage is specified as potential difference (PD), i.e. \nthe voltage when connected to a 50 ohm load.\n\nTo convert uV to dBm :-\n\ni) work out the power in Watts :-  P=V^2/R so 25uV equates to 12.5pW or \n0.0000000000125W.\n\nii) Multiply by 1000 to give the answer in mW; i.e. 0.0000000125mW.\n\niii) Take the logarithm and multiply by 10 to give -79dBm.\n\n\nHowever, I'm not sure where 12.5uV comes from - a typical VHF receiver \nneeds about 0.25uV or better - that's -119dBm; if your radio really \nneeds 25uV then there is something seriously wrong.\n\nregards\n\nGrant  G8UBN\n\n",
    "attachments": []
}