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{
    "url": "https://mailman.amsat.org/hyperkitty/api/list/[email protected]/email/D6EZWLDVP75RZ5ZQKSWU3J4GDBKM25LW/?format=api",
    "mailinglist": "https://mailman.amsat.org/hyperkitty/api/list/[email protected]/?format=api",
    "message_id": "[email protected]",
    "message_id_hash": "D6EZWLDVP75RZ5ZQKSWU3J4GDBKM25LW",
    "thread": "https://mailman.amsat.org/hyperkitty/api/list/[email protected]/thread/EKUDXYKHK5GFZBJBDILTUCJRDYFTDOTJ/?format=api",
    "sender": {
        "address": "gerhardstein (a) montana.com",
        "mailman_id": null,
        "emails": null
    },
    "sender_name": "Larry Gerhardstein",
    "subject": "[amsat-bb] Re: probably simple",
    "date": "2010-01-08T07:42:56Z",
    "parent": "https://mailman.amsat.org/hyperkitty/api/list/[email protected]/email/EKUDXYKHK5GFZBJBDILTUCJRDYFTDOTJ/?format=api",
    "children": [],
    "votes": {
        "likes": 0,
        "dislikes": 0,
        "status": "neutral"
    },
    "content": "Bob W7LRD,\n\nI disagree that Doppler shift will be zero when your window to work \nnorthern EU is optimum.\n\nIn SatPC32, I just did a Tracking->Preview and determined that when the \nAO-07 footprint includes both the northwest USA and northern Europe, the \ndown link Doppler is +2.8 and up link Doppler is -8.3.\n\nNote, the numbers +2.8 and -8.3 were for orbit #60844.  I also \ndetermined that if a different orbit, then you get different Doppler \nshifts.  Determine the pass that you wish to attempt a contact and use \nthe Doppler numbers you get from Tracking->Preview for that pass.\n\nNext pick a frequency using VFO mode in SatPC32 and do some \nexperimenting.  You may need to waste a window of opportunity, but using \na ratio of -8.3/2.8 uplink to downlink Doppler, you should be able to do \na respectable calculation.\n\nAnother problem: The Doppler for the station in northern-EU will likely \nbe different than yours.  This means you might wish to coordinate with \nthe station over there as you attempt contact. When I tried to enter \ngrid JPnn into SatPC32, it would not accept it.  It calculated NAN (not \na number) for latitude.  Don't know what that's about.\n\nHowever if you're using CW & not SSB, this may make little difference.  \nAs long as you're getting a CW signal in the band pass of your RX, you \nshould be able to copy.\n\nAnd remember, the squeaky wheel gets the oil.  Keep making noise about \nthis on this BB until something works.\n\nI know you wanted a simpler answer.  Hope this does not seem too \ncomplicated.  The Trig/Math to work this out is possible, but tricky.\n\nGood luck.\n\n73, Larry W7IN (home=DN27 Plains, Montana)\n\n",
    "attachments": []
}