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{
    "url": "https://mailman.amsat.org/hyperkitty/api/list/[email protected]/email/STMM75HDDNSXLUQXRO33TBRY53Z2YTDT/?format=api",
    "mailinglist": "https://mailman.amsat.org/hyperkitty/api/list/[email protected]/?format=api",
    "message_id": "[email protected]",
    "message_id_hash": "STMM75HDDNSXLUQXRO33TBRY53Z2YTDT",
    "thread": "https://mailman.amsat.org/hyperkitty/api/list/[email protected]/thread/STMM75HDDNSXLUQXRO33TBRY53Z2YTDT/?format=api",
    "sender": {
        "address": "st2nh (a) yahoo.com",
        "mailman_id": "18d20a49064d4389a903c077203dda96",
        "emails": "https://mailman.amsat.org/hyperkitty/api/sender/18d20a49064d4389a903c077203dda96/emails/?format=api"
    },
    "sender_name": "nader omer",
    "subject": "[amsat-bb]  ISS lift off distance !",
    "date": "2009-01-18T01:53:42Z",
    "parent": null,
    "children": [],
    "votes": {
        "likes": 0,
        "dislikes": 0,
        "status": "neutral"
    },
    "content": "Hi All\n \nWho could remind me of the physical equation that calculate the lift off distance depending on time different between the old and the new  AOS (e.g ISS)?\n \nNader. st2nh\nwww.st2nh.com\n\n\n      \n",
    "attachments": []
}